UDF does not have separate preallocated table of inodes. So similarly to
XFS we pretend that every free block is also a free inode in statfs(2)
output. Clarify this in a comment.
Signed-off-by: Jan Kara <jack@suse.cz>
buf->f_blocks = sbi->s_partmaps[sbi->s_partition].s_partition_len;
buf->f_bfree = udf_count_free(sb);
buf->f_bavail = buf->f_bfree;
+ /*
+ * Let's pretend each free block is also a free 'inode' since UDF does
+ * not have separate preallocated table of inodes.
+ */
buf->f_files = (lvidiu != NULL ? (le32_to_cpu(lvidiu->numFiles) +
le32_to_cpu(lvidiu->numDirs)) : 0)
+ buf->f_bfree;