tcp: Fix bind() regression for v6-only wildcard and v4(-mapped-v6) non-wildcard addre...

tcp: Fix bind() regression for v6-only wildcard and v4(-mapped-v6) non-wildcard addresses.

Jianguo Wu reported another bind() regression introduced by bhash2.

Calling bind() for the following 3 addresses on the same port, the
3rd one should fail but now succeeds.

  1. 0.0.0.0 or ::ffff:0.0.0.0
  2. [::] w/ IPV6_V6ONLY
  3. IPv4 non-wildcard address or v4-mapped-v6 non-wildcard address

The first two bind() create tb2 like this:

  bhash2 -> tb2(:: w/ IPV6_V6ONLY) -> tb2(0.0.0.0)

The 3rd bind() will match with the IPv6 only wildcard address bucket
in inet_bind2_bucket_match_addr_any(), however, no conflicting socket
exists in the bucket.  So, inet_bhash2_conflict() will returns false,
and thus, inet_bhash2_addr_any_conflict() returns false consequently.

As a result, the 3rd bind() bypasses conflict check, which should be
done against the IPv4 wildcard address bucket.

So, in inet_bhash2_addr_any_conflict(), we must iterate over all buckets.

Note that we cannot add ipv6_only flag for inet_bind2_bucket as it
would confuse the following patetrn.

  1. [::] w/ SO_REUSE{ADDR,PORT} and IPV6_V6ONLY
  2. [::] w/ SO_REUSE{ADDR,PORT}
  3. IPv4 non-wildcard address or v4-mapped-v6 non-wildcard address

The first bind() would create a bucket with ipv6_only flag true,
the second bind() would add the [::] socket into the same bucket,
and the third bind() could succeed based on the wrong assumption
that ipv6_only bucket would not conflict with v4(-mapped-v6) address.

Fixes: 28044fc1d495 ("net: Add a bhash2 table hashed by port and address")
Diagnosed-by: Jianguo Wu <wujianguo106@163.com>
Signed-off-by: Kuniyuki Iwashima <kuniyu@amazon.com>
Link: https://lore.kernel.org/r/20240326204251.51301-3-kuniyu@amazon.com
Signed-off-by: Jakub Kicinski <kuba@kernel.org>